Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Draw line BC = 11 cm. Make an angle of 30° at B and 90° at C using a protractor. Bisect angles B and C, and these bisectors will meet at one-point X. Now draw perpendicular bisectors on BX and CX, which will cut the line segment BC on point Y and Z respectively. Now join XY and XZ to get the required triangle XYZ.
It is given that we have to construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. We have drawn the triangle using a compass and ruler and justified the construction.
NCERT Solutions for Class 9 Maths Chapter 11 Constructions, 11.1 & 11.2
Punjabi] Construct a triangle XYZ in which angle Y = 30^@, angle Z =
Question 4 - Construct triangle XYZ - angle Y = 30, Z = 90, XY + YZ+ZX
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. - Sarthaks eConnect
Class 9 RD Sharma Solutions - Chapter 17 Constructions- Exercise 17.3 - GeeksforGeeks
Construct a triangle XYZ in which angle Y = 30o, angle Z = 90o and XY + YZ + ZX =11cm. - 8mx6xe0zz
Construct a triangle XYZ in which XY = YZ = 4.5 cm and ZX = 5.4 cm. Draw the circumcircle of the triangle.
Construct triangle xyz in which Angle y = 45 degree angle Z = 30 degree also xy + y z + Z X equals to 10 cm
construct a triangle xyz in which y=30 z=90 and xy+yz+zx=11 in
Construct a triangle ( mathrm { ABC } ) in which ( mathrm { BC } = 8 mathrm { cm } , angle mathrm { B } = 45 ^ {
YZ is a right-angled triangle with ( angle mathrm { X } = 90 ^ { circ } , mathrm { XY } = 9 mathrm { cm } , ) and ( mathrm { YZ } = 12 mathrm { cm } . ) OX is perpendicular to YZ. ( sin 00 x ) 11 1 ( x ) ( therefore 1 )
Telugu] Construct DeltaXYZ in which angleY = 30^(@), angleZ = 60^(
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11cm #class_9th #ncert