Prove that tanA tan(90 - A) = cotA cot(90 - A) = sinA sec(90 - A

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SinA. sec(90-A).tanA/cosec(90-A). cosA. cot(90-A) =tan(90-A)/cotA

Prove the following: (tan(90^0-A)cotA)/(cos e c^2A)-cos^2A=0

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1. Express the trigonometric ratios sinA,secA and tanA in terms of

prove that tan(90-A)+cot(90-A)/sec(90-A)=cosec(90-A)​

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What is the formula of tan(90 - A)? - Quora