In the given figure, BOC is a diameter of a circle and AB = AC. Then, ∠ABC = ? a 30∘ b 45∘ c 60∘ d 90∘

In the given figure, BOC is a diameter of a circle and AB = AC. Then, ∠ABC = ? a 30∘ b 45∘ c 60∘ d 90∘
In the given figure- BOC is a diameter of a circle and AB - AC- Then- -ABC - - a 30- b 45- c 60- d 90

In figure, BC is a diameter of the circle and angleBAO=60

In the given figure, BOC is a diameter of a circle and AB = AC

AB is a diameter of a circle and AC is its chord such that angle BAC equals to 30. If tangent at C intersects AB extended D, then prove that BC equals

In the given figure, O is the centre of the circle. If ∠ ACB=50

In the given figure, /_ AOB = 90^(@) and /_ ABC = 30^(@) . Then /_

Angle in a Semicircle - GCSE Maths - Steps, Examples & Worksheet

In figure, if angleAOB=90^(@) and angleABC=30^(@), then angleCAO is equal to, 9, CIRCLES

In the given figure, DeltaABC is an isosceles triangle with AB=AC and angleABC=50^o. Find angleBDC and angleBEC respectively.100^o, 60^o50^o, 120^o60^o, 80^o80^o, 100^o

In the given figure, BOC is a diameter of a circle and AB =AC . Then

In Fig., ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If angle DBC=55^{o} and angle BAC=45^{o}, angle BCD.

In the figure, C and D are the points on the semicircle inscribed

ABCD is a rhombus such that ∠ACB = 40º. Then ∠ADB is a. 40º, b

In the given figure AB is the diameter of the circle, PM bisects angle APB then the measure of angle ABM is45^{circ}30^{circ}15^{circ}60^{circ}

In the given figure, BOC is the diameter of the circle with centre

Triangle ABC is inscribed on a circle of radius 10. AB=19, AC=12, and [ABC] =65.25. What is BC? Round your answer to the nearest hundredth. - Quora