Prove that : cos20°/sin70° + cosθ/sin(90° - θ) = 2 - Sarthaks

Prove that : cos20°/sin70° + cosθ/sin(90° - θ) = 2

सिद्ध कीजिए कि : (cos 20 deg)/(sin 70 deg) + (cos

prove that- sin(70*+theta) - cos(20*-theta)=0 - Maths

सिद्ध कीजिए कि(cos theta)/(sin(90^(@)-theta))+(sin

sin 70 Prove that cos 20 sec 70 cosec20_2cos 70 - cosec20 = 0.

cos20/sin70 + 2costheta/sin (90-theta) = k/2 find k​

Simplify the following: Cos20°/Sin70° + CosA/Sin(90°-A)

How to prove sin 70°/cos 20° = 1 without using a trigonometry

Cos70/sin20 + cos59/sin31 - 8sin2 30

Solve the following equations: (i) sin 5x – sin x = cos 3x (ii) 2

सिद्ध कीजिए कि(cos theta)/(sin(90^(@)-theta))+(sin

cos 20^(@)),(sin 70^(@), cos 70^(@))

Find the value off the following: cos70°/sin20° + (cos55° cosec35

Prove that cos(π + θ)cos(-θ)/cos(π - θ)cos(π/2 + θ) = -cotθ